There are 3 consecutive integers with a sum of 93

Question

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Answer 1

Let x be the 1st integer, x + 1 be the 2nd integer, and x + 2 be the 3rd integer.  Now set up an addition equation:  x + (x + 1) + (x + 2) = 93.  Add like terms together and simplify the equation to 3x + 3 = 93.  Subtract 3 from both sides of the equation to obtain 3x = 90.  Now divide both sides by 3 to get x = 30.  Now substitute 10 in the place of x in our integer expressions in the first sentence, therefore the three integers are 30, 31, and 32.  Do a check and add the three consecutive integers together to see if you get 93.  30 + 31 + 32 does equal 93 so 30, 31, and 32 are the correct answers.

Answer 2

You are looking for three consecutive integers whose sum is 93. First, divide 93 by 3 and get 31. Go one above 31 and one below. You get 30, 31 and 32 which sum to 93. This method works in most cases. If the sum is not divisible by the number of integers (3 in this case) then start with the integer closest to the quotient.