David W. answered 11/07/15
Experienced Prof
First, let's review what "the square" looks like:
(x + a)(x + a)
x^2 + ax + ax + a^2
x^2 + 2ax + a^2
Now, we must find the value for "a" in this expression.
The problem gives us x^2 -9x ... So, 2a=-9 and a=-9/2
O.K., that tells us that (x-9/2)(x-9/2) = x^2 -9x + 81/4 [this is a perfect square]
Now, what needs to be done to the given equation to make it have that expression on the left side?
x^2 - 9x -38 = -9
x^2 - 9x = 29 [add 38 to each side]
x^2 - 9x + 81/4 = 29 +81/4 [add 81/2 to each side]
x^2 - 9x + 81/4 = (116+81)/4 [convert to improper fraction]
x^2 - 9x + 81/4 = 197/4 [now the left side is O.K.]
(x-9/2)(x-9/2) = 197/4
x-9/2 ≅ 14.04/2 or x-9/2 ≅ -14.04/2 [take square root of each side]
x ≅ (14.04 + 9)/2 or x ≅ (-14.04 + 9)/2 [add 9/2 to each side]
x ≅ 23.04/2 or x ≅ -5.04/2