g(x)=x^3-1

Question

i have a homework problem  from pre calculus and i dont understand how to solve it  

Answer 1

Are they asking you to graph it?

 

I'm reading the problem as g(x) = x³ - 1.

 

Since it's Pre-Calc, I'm guessing they probably want you to graph it.

 

The parent function is f(x) = x³ .

 

 

So 3 pts on f(x) are:  (-1, -1), (0, 0), and (1, 1).  Since the -1 will result in a downward shift of 1 unit,

the points on the graph of g(x) = x³ - 1 would be (-1, -2), (0, -1), and (1, 0).

 

You can graph it from there.  It's concave down on the left side of the y axis and concave up on the right side of the y axis.

 

Hope this helps.  

 

Jason

Answer 2

Hi Yozeline;

I am not exactly certain what this is...

g(x)=x^3-1

or

g(x)=(x³)^-1

 

Let's do both...

g(x)=x^3-1=x²

This is because this is...

(x)(x)(x)

 

g(x)=(x³)^-1

This can also be expressed as...

g(x)=(x³)/(x¹)=(x³)/(x)

This is because (x)(x)(x)/(x)

Henceforth...

x²

 

It would be easier to say 3-1=2.

 

Is that the answer you are looking for?