Dulian T.

asked • 11/02/15

Calculus question

Suppose that f : [0, 1] −→ [0, 1] is a continuous function. Prove that f has a fixed point in [0, 1], i.e., there is at least one real number x ∈ [0, 1] such that f(x) = x

2 Answers By Expert Tutors

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Michael J. answered • 11/02/15

Tutor
5 (5)

Mastery of Limits, Derivatives, and Integration Techniques

Faraz R.

tutor
You are right but I think this has to deal with the Intermediate value theorem.  It's not only linear functions that can be continuous from 0 to 1. 
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11/02/15

Michael J.

Since we have a continuous function, we can use the intermediate value theorem.  In order for f(x) to have at least one real root, f(x) must change signs from the starting point to the end point of the interval.  Or somewhere within the interval, f(x) is zero.
 
f(x) = x
 
 
Evaluate f(0) and f(1) in this order.
 
f(0) = 0
 
f(1) = 1
 
Because f(0) is 0, x=0 is a root at the point (0, 0).
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11/02/15

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