Write sec t in terms of tan t if t is in quadrant II: sec t =A sqrt{B+C^2}, the sign A (input + or -) is ; the constant B is ; the function C is

Question

I need to see all the steps for this question so I could be able to it on my own next time. Show me in full detail of how you arrive at the answer. You have to find the sign A (input + or -) ; the constant B and the function C. 

Answer 1

If t is in quadrant 2, then sect < 0.

 

1 + tan²t = sec²t, so sect = ±√(1+tan²t)

 

But, since t lies in quadrant 2, sect = -√(1+tan²t)

 

So, A = -1, B = 1, and C = tant