The sum of 3 consecutive numbers is 72. what are the smallest of these numbers

Question

Have to write an equation and solve

Answer 1

aight cool so since they are consecutive numbers let the 3 numbers be

 

x , x+1, x+2

 

then  your sum would be   x + ( x + 1 ) + ( x + 2 ) = 72

 

so now just add em up

 

3x + 3 = 72

 

x = 69 / 3

 

x = 23

 

the three numbers are 23,24,25

 

 

 

 

 

 

Answer 2

Here's what we know:

a + b + c = 72

a = b - 1

c = b + 1

 

(b - 1) + b + (b + 1) = 72

Simplify

3b = 72

b = 24

 

a = 24 - 1

a = 23