Inactive Tutor answered 10/08/13
Tutor
New to Wyzant
P = Probability of being defective = 0.03
1-P = Probability of not being defective = 0.97
12 C 5 = the number of combinations of 5 defects out of 12
(P)5(1-P)7= the probability for a single combination of 5 defects out of 12
The probability of exactly 5 defects = (12 C 5)(P)5(1-P)7