What is the answer?

6a

^{2}+41a+63=063=7*9

(_a+7)(_a+9)

6=2*3

(3a+7)(2a+9)=0

3a+7=0; 2a+9=0

3a=-7; 2a=-9

a= -7/3; a= -9/2

CHECK:

FOIL

F: 3a*2a = 6a

^{2}0: 3a*9 = 27a

I: 7*2a = 14a

L: 7*9 = 63

= 6a

^{2}+27a+14a+63= 6a2+41a+63

REPLACE:

6(-7/3)

^{2}+41(-7/3)+63 = 06(-9/2)

^{2}+41(-9/2)+63 = 0