
Yossi Y. answered 10/01/13
Electronic Engineering Background and Teaching/Tutoring Experience
This is the quadratic equation aX^2 + bX + C
Where X is the unknown variable to be resolved, and a,b,c are constants
Solutions:
X12 = ( - b +- √ (b^2 – 4ac) )/2a
Solution 1:
X1 = ( -18 + √ (18^2 – 4*6*9) )/2*6 = ( -18 + √ (324 – 216) )/12 = ( -18 + √ (108) )/12
X1 = -18/12 + √ (108)/12
Solution 2:
X2 = ( -18 - √ (18^2 – 4*6*9) )/2*6 = ( -18 - √ (324 – 216) )/12 = ( -18 - √ (108) )/12
X2 = -18/12 - √ (108)/12