algebra word problem

Question

Jim had $2.25 in dimes and nickels. If he had twice as many dimes as nickels, how many of each coin did he have?

Answer 1

let n = the value of the nickels, then 2n = the value of the dimes

 

so, n + 2n = $2.25; solving; 3n = $2.25; n = $0.75

 

so, the value of the nickels is $0.75, which when divided by $0.05/nickel gives 15 nickels

 

$2.25 - 0.75 = $1.50, the value of the number of dimes, which when divided by $0.10/dime gives 15 dimes