Find the differential of each function.

Question

(a) y= tan(sqrt 3t)

Answer 1

y = tan((3t)^1/2)

 

 

To find the derivate, we use the chain rule.

 

y' = [3 * (1 / 2)(3t)^-1/2] * sec²((3t)^1/2)

 

y' = (3 / 2)(3t)^-1/2 * sec²((3t)^1/2)