A fair die

Question

A fair die is thrown 10 times. What is the probability of getting point 1 on at most 9 of the 10 throws?

Answer 1

To calculate this probability you use the formula P(9)=C10,9P^9q^1

in our case p=1/6, g=5/6, C10,9=10!/(9!(10-9)!)=10  so P(9)=10x(1/6)^9x(5/6)^1=8.269x10^-7