
Peter D. answered 10/30/15
Tutor
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PhysicsPhD/MathBS -- Recent teaching and tutoring experience
P(1st is 3 or 2nd is 3 | sum of 1st and 2nd is 5)
The possibilities of the sum being 5 are:
1 4
4 1
2 3
3 2
So there are only 2 possibilities for the above P : 2 3 ; 3 2
P(1st is 3 or 2nd is 3 | sum of 1st and 2nd is 5) = 2/4 = 1/2