In order to get a complex number into standard form, you must not have any complex numbers in the denominator.
So first we must simplify the problem. For clarity, I am going to write out the problem.
Whenever you are multiplying problems that have (a-bi)*(a+bi), you can use the shortcut (a^2-((b^2)(i^2))).
This is called a difference of squares.
Therefore we now have
_______________ = _______________
Since i^2=-1, we can simplify this to be
Distribute the 13
Now we need to get this answer into standard form, so we are going to use the difference of squares method and multiply by the fraction
We are able to do this because the fraction above is equal to one, and multiplying any number by one gives us the same number.
So now we have
= ________ * ______
Using the FOIL method you can simplify the numerator and using the difference of squares method for the denominator you should have
DENOMINATOR: (5-i)(5+i) = (25-i^2)
So, once you FOIL the top, what are you left with?
Try working this problem with the suggestions I gave you and see if you can simplify it to Standard form.
Let me know if you have any further questions!