Find f'(x) and f"(x): f(x)=x/x^2-1

Question

Please help

Answer 1

Jessica,

 

Thanks for the clarification. In this case you use the quotient rule since you have one function on top and one on the bottom as follows

dy/dx (u/v) = (vu'-uv')/v^2

where u=x and v=x^2-1

Then u'=1 and v'=2x

 

Plugging into the formula:

(2x-x(2x))/(x^2-1)^2=(2x-2x^2)/(x^2-1)^2

 

Hope that helps!