Deanna L. answered 10/01/15
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Electrical engineering major and music lover with MIT degree
Blake,
The probability of 9 or more successes in a sample size of 11 is P(9)+P(10)+P(11) where
P(x,n,p)=combination(n,x)p^x * q^(n-x) and q=1-p
P(9)=combination(11,9) * .5^9 * .5 ^ 2 =55 * .5 ^ 11=.026855
P(10)=combination(11,10) * .5^11=11*.5^11=.00537
P(11)=combination(11,11) * .5^11=1*.5^11=.000488
So P(9)+P(10)+P(11)=.0327
Hope that helps!