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calculus problem

The distance of a particle from it's starting point at time t second is given by 8 = 80t - 16t^2
 
what is the velocity of the particle after 2 seconds?

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Parviz F. | Mathematics professor at Community CollegesMathematics professor at Community Colle...
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 Of what?
  
 Ok, 
   Velocity is rate of change of displacement:
 
   Given : Displacement 
 
   D = - 16t2 + 80t - 8
        
     Velocity is the derivative of displacement:
 
      V =  dD/ dt = -32t + 80
    
      V(2) = -32(2) +80 = 16