The distance of a particle from it's starting point at time t second is given by 8 = 80t - 16t^2 what is the velocity of the particle after 2 seconds? 9/25/2013 | Faisal from Henderson, NV | 1 Answer | 0 Votes Mark favorite Subscribe Comment
Of what? Ok, Velocity is rate of change of displacement: Given : Displacement D = - 16t^{2} + 80t - 8 Velocity is the derivative of displacement: V = dD/ dt = -32t + 80 V(2) = -32(2) +80 = 16 9/25/2013 | Parviz F. Best answer Comment