find the derivative of the function g(x)=4^c/x

Question

Please help me 

Answer 1

g(x) = 4^(c/x) ln g(x) = (c/x) ln 4 Taking an implicit derivative, (1/g(x)) g'(x) = (-c/x^2) ln 4 g'(x) = - c [ln 4] g(x)/x^2 = [ -c [ln 4] 4^(c/x)]/x^2

Answer 2

Jessica,

 

Assuming 4^c is a constant, then we can assume this is simply differentiating x^-1 and multiplying it by 4^c. The differentiation of x^-1 means we multiply by the exponent power (-1) and subtract 1 from the exponent power (-1-1). In this case we get g'=-4^c/x^2

 

Hope that helps!