
Joseph F. answered 10/03/15
Joe's Math, Science and Chess
We can find this derivative by following the Product Rule. If u and v are both functions of x, and their derivatives in x are u' and v', then: d(uv)dx = u'v + uv' Using this, we differentiate the function as follows: d(e^xcos(x))dx = (e^x)cos(x) - (e^x)sin(x) or = (e^x)(cos(x) - sin(x))