Where does the normal line to the parabola, y=x-x^2 at the point (-1,0) intersect the parabola a second time? Illustrate with a sketch

Question

Please help me 

Answer 1

y=x-x^2 at the point (-1,0)

but

0 doesn't = -1-(-1)^2 = -1-1=-2

so the problem was miscopied, as (-1,0) is not on the parabola, the problem

might have read the point (1,0) which is on the parabola

y' = 1-2x = slope of the parabola

slope at (1,0) = 1-1 = 0

normal at that point has the negative inverse slope which is undefined.

(1,0) is the vertex and the normal through that point does not intersect the parabola a 2nd time

the normal line at that point has an equation

x=1

the problem needs either a different point or a different parabola

to make sense, to have 2 intersections of the normal line with the parabola