
Shradha S. answered 09/24/15
Tutor
4
(1)
Experienced Maths Teacher with Master's Degree in Mathematics
cos(x)tan4(x) = cos x * (sinx/cosx)4
= cos x *(sin4x/cos4x)
=sin4x / cos3x
=(sin2x)2 / cos3x
= [(1-cos2x)/2]2 / [(cos3x+3cosx)/4]
= [(1-cos2x)2/4 ] / [(cos3x+3cosx)/4]
=(1-cos2x)2 / (cos3x+3cosx)
=(1 + cos22x - 2cos2x) /(cos3x+3cosx)
=[1+{ (cos4x+1)/2} - 2cos2x ] / (cos3x+3cosx)
=( 2+ cos4x+ 1 - 4cos2x) / 2 (cos3x+3cosx)
=(cos4x - 4cos2x +3) / 2(cos3x+3cosx)