Mark M. answered 09/15/15
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Retired math prof. Calc 1, 2 and AP Calculus tutoring experience.
For the function to be continuous at x = 2, the two pieces of the graph must fit together at x = 2. In other words, Ax3 = 7-Ax when x = 2.
So, A(2)3 = 7 - A(2)
8A = 7 - 2A
10A = 7
A = 7/10