Roman C. answered 09/14/15
Tutor
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Masters of Education Graduate with Mathematics Expertise
First of all, let's assume all the magazines are distinct.
There are 8+7+3 = 18 magazines on the rack in total.
Then the total number of ways to choose 4 is
C(18,4) = 18·17·16·15 / 4! = 3060
Part 1:
There are C(8,2) = 8·7 / 2! = 28 ways to choose the two Newsweeks.
There are C(10,2) = 10·9 / 2! = 45 ways to choose two that are not Newsweek.
Thus the probability of getting two Newsweek among the four drawn is
28·45 / 3060 = 7 / 17
Part 2:
You must choose December 1st Times magazine.
There are C(17,3) = 17·16·15 / 3! = 680 ways to choose the other three magazines.
Thus the probability of getting the December 1st Times magazine among the four drawn is
680 / 3060 = 2 / 9
There are C(17,3) = 17·16·15 / 3! = 680 ways to choose the other three magazines.
Thus the probability of getting the December 1st Times magazine among the four drawn is
680 / 3060 = 2 / 9