Dominic S. answered 09/14/15
Tutor
5.0
(240)
Math and Physics Tutor
First, what is the definition of the derivative? It is:
f'(x) = limh->0 (f(x+h)-f(x))/h)
(Conceptually, this is just the average slope over a distance h, as h goes to zero)
Plugging in our specific equation, this gives
(4 + 8(x+h) - 5(x^2+2xh+h^2) - (4 + 8x - 5x^2))/h
= (8x + 8h - 5x^2 - 10xh - 5h^2 - 8x + 5x^2)/h
= (8h - 10xh - 5h^2)/h
= 8 - 10x - 5h
Which, as h goes to 0, is just
8 - 10x
Both the original function and its derivative will yield a valid output for any x you use, so both domains are (-∞,∞)