Hi Liy,
Let's begin by assigning three letters to represent our three unknowns:
x = number of bikes
y = number of tandems
z = number of tricycles
Now let's come up with a system of three equations to solve for our three unknowns:
Equation #1 (based upon number of seats):
x + 2y + z = 135 (total seats)
x (1 seat per bike)
y (2 seats per tandem)
z (1 seat per tricycle)
Equation #2 (based upon number of handle bars)
x + y + z = 118 (total handle bars)
x (1 handle bar per bike)
y (1 handle bar per tandem)
z (1 handle bar per tricycle)
Equation #3 (based upon number of wheels)
2x + 2y + 3z = 269 (total wheels)
x (2 wheels per bike)
y (2 wheels per tandem)
z (3 wheels per tricycle)
Now let's group our three equations together for solution and manipulate them to solve for each unknown:
Equation #1: x + 2y + z = 135
Equation #2: x + y + z = 118
Equation #3: 2x + 2y + 3z = 269
Equation #4: Equation #1 - Equation #2
(eliminate unknowns x and z)
Equation #4: y = 17 (number of tandems)
Equation #5: (replace y in Equation #2
with 17 from Equation #4)
Equation #5: x + 17 + z = 118
Equation #5: x + z = 118 - 17
Equation #5: x + z = 101
Equation #6: (replace y in Equation #3
with 17 from Equation #4)
Equation #6: 2x + 2(17) + 3z = 269
Equation #6: 2x + 34 + 3z = 269
Equation #6: 2x + 3z = 269 - 34
Equation #6: 2x + 3z = 235
Equation #7: (multiply each term in Equation #5
by 2)
Equation #7: 2x + 2z = 202
Equation #8: Equation #6 - Equation #7
(eliminate unknown x)
Equation #8: z = 33 (number of tricycles)
Equation #9: (replace y in Equation #2
with 17 from Equation #4 and
replace z in Equation #2
with 33 from Equation #8)
Equation #9: x + 17 + 33 = 118
Equation #9: x + 50 = 118
Equation #9: x = 118 - 50
Equation #9: x = 68 (number of bikes)
Finally, we can verify each of our answers by plugging them back into our three original equations and evaluate each equation to ensure that each equation is true:
Equation #1: x + 2y + z = 135
68 + 2(17) + 33 = 135
68 + 34 + 33 = 135
102 + 33 = 135
135 = 135 (equation is true)
Equation #2: x + y + z = 118
68 + 17 + 33 = 118
85 + 33 = 118
118 = 118 (equation is true)
Equation #3: 2x + 2y + 3z = 269
2(68) + 2(17) + 3(33) = 269
136 + 34 + 99 = 269
170 + 99 = 269
269 = 269 (equation is true)
Since we see that all three original equations evaluated as true using each of our answers, we are confident that our answers are correct.
Thanks for submitting this problem and glad to help.
God bless, Jordan.