Arthur D. answered 09/06/15
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n(A)=49
n(B)=64
n(A')=37
n(A∩B)=30
because of the intersection being 30, there are 49-30=19 elements in A only
because of the intersection being 30, there are 64-30=34 elements in B only
if n(A')=37 and B has 34 elements only in B, there must be 3 other elements in the Universe not in A or in B
n(B')=19 elements from A plus the 3 elements in the Universe not in A or in B
n(AUB')=19+3=22 because we don't count the 19 elements in A twice