If y varies inversely as the square of x, and y=1/8 when x=1, find y when x=5.

Question

I'm not sure the answer to  this question.

Answer 1

yx² = k, where k is some constant

 

(1/8)(1²) = k

1/8 = k

 

y(5²) = 1/8

25y = 1/8

y = 1/200