Mark M. answered 09/02/15
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Retired math prof. Calc 1, 2 and AP Calculus tutoring experience.
Let x = horizontal distance of the bow of the boat from the dock at time t
y = length of rope at time t
We have a right triangle. At time t, the legs of the triangle have lengths 1 and x and the hypotenuse has length y.
By the Pythagorean Theorem, x2 + 12 = y2
We are given: dy/dt = -1.1
We are to find dx/dt when x = 10 m
Differentiate x2 + 1 = y2 with respect to t:
2x(dx/dt) + 0 = 2y(dy/dt)
So, dx/dt = y(dy/dt)/x When x = 10, y2 = 101
y = √101
= (-1.1)(√101)/10
= -11(√101)/100
When x = 10 m, the boat is approaching the dock at the rate of 11√101/100 m/sec.