Mohammad N. answered 11d
Experienced Math Professor 35 Years Teaching Algebra; Calculu
For a curve y=f(x) rotated around a vertical line x=0 , the surface area is
where
•r(x) is the horizontal distance from the point (x,f(x)) to the line x=0 .
Here, a=-1, so
r(x)= ⌊ x- (-1) ⌊=x+⌈1
(because on ⌈-1, 2⌉, we have x+1≥0).
s =2 π ∫ (x+1) √1+(7/64 x2 + 5/34 x4 + 9/8 x2 -3/2 x -2 ) 2 dx on ⌈-1, 2⌉