Identify the beginning of a sample period for the function:

Question

f (t) = 4sec(3t −6π)

 

a. x=2pi

b. x=1

c. x=2pi/3

d. x=pi

Answer 1

f (t) = 4sec(3t −6π)

Multiple Choice variables : a. x=2pi, b. x=1, c. x=2pi/3 and d. x=pi

The function = f(t) = 4 x sec x (3t - 6pi) x = times or multiply

Note: The beginning of a period can be found by seting the argument of the secant function to zero.

4sec(3t-6pi)

First Step

Set the argument of the secant function to 0.

3t-6pi=0

Secondly, Solve for t

3t-6pi=0 isolate t by dividing both sides by 3

3

t = 6pi perform division t = 2 pi

3

Solution:

The beginning of a sample period for the function is 2 pi

multiple choice answer is (a) 2 pi

I hope the mathematical calculations (step by step approach) was helpful. Please let me know if you require any more assistance. If anyone in my neighborhood is interested in setting up an in-person math tutoring session. I look forward to hearing from them. Have an amazing day. Doris H.