Mark M. answered 08/23/15
Tutor
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Retired math prof. Calc 1, 2 and AP Calculus tutoring experience.
TRUE:
By the Fundamental Theorem of Calculus, if F(x) = ∫√(t3+1)dt from t = 0 to t = x then F'(x) = √(x3+1). So, F'(2) = √(23+1) = √9 = 3.