Roman C. answered 08/26/15
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Masters of Education Graduate with Mathematics Expertise
Assuming independence, since all students are equally likely to connect, this is a binomial setting. We are given n=2 students are chosen and p=0.4 for the probability a students logs in. So the distribution is for the number of students connecting is Bin(2,0.4).
The PMF is
P(N=0) = 0.62 = 0.36
P(N=1) = 2(0.4)(0.6) = 0.48
P(N=2) = 0.42 = 0.16
And the support is {0,1,2}.