Edward C. answered 08/19/15
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Caltech Grad for math tutoring: Algebra through Calculus
P(G) = 2/3
Expected number of girls in 5 children = P(G)*5 = 10/3 ~ 3.33
P(at least 2 girls) = 1 - [P(0 girls) + P(1 girl)]
P(0 girls) = (1/3)5 = 1/243
P(1 girl) = 5C1 * (2/3)1 * (1/3)4
= 5 * (2/3) * (1/81) = 10/243
So P(at least 2 girls) = 1 - [1/243 + 10/243] = 1 - 11/243 = 232/243 ~ 0.9547 ~ 95.47%