Andrew M. answered 08/19/15
Tutor
New to Wyzant
Mathematics - Algebra a Specialty / F.I.T. Grad - B.S. w/Honors
a) b8(2b)4
First look at the parentheses... (2b)4
For exponents (ab)n = anbn so (2b)4 = 24b4 = 16b4 so we have
b8(2b)4 = 16(b8)(b4)
For exponents anam = a(n+m) so b8b4 = b(8+4) = b12
Final answer: 16b12
b. (6y3)4/(2y5)
Numerator: 64(y3)4 = 1296
1296y(3)(4) = 1296y12
1296y12/(2y5)
= 648y12/y5
For exponents a-n = 1/an or 1/an = a-n so 1/y5 = y-5
648y12y-5
Again: y12y-5 = y(12-5) = y7
Final answer: 648y7
Andrew M.
08/19/15