[sec(π/4)cos(2π/3)]/[tan(π/6)/csc(3π/4)].
=cos(2π/3)/[cos(π/4)tan(π/6)sin(3π/4)]
=-.5/[(√2/2)(√3/3)√2/2)]=-3/√3=-√3
The only tricky parts are finding the reference angles for
2π/3 and 3π/4
Amber G.
asked • 08/18/15Find the Exact Value
Find the exact value of [sec(pi/4)cos(2pi/3)]/[tan(pi/6)/csc(3pi/4)]. You must have exact values, no decimals.
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Arthur D.
08/18/15