How can I find w if: logw=1/5logx -logy?

Question

 I know the answer is (x^1/5)/y but I can't seem to find the steps. Please help!

Answer 1

logw = (1/5)logx - logy

 

logw = log(x^1/5) - logy      [r(loga) = log(a^r)]

 

logw = log[x^1/5/y]            [logA - logB = log(A/B)]

 

So, w = x^1/5y