Ketaki M. answered 08/12/15
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New to Wyzant
Ketaki M Math,SAT,ACT.GRE,AP CAlculus
when x is 0,sin y is 0 which implies y is 0
when x =1/2 implies sin y =1/√2 ⇒y= π/4
so your limits are from 0 to π/4
your integrand is siny /√1-sin²y
ie siny/cos y
ie tany
π/4
hence your integration problem converts to 0∫tan y
now do it
Ketaki M.
see you substituted √x as sin y
this also means that x = sin²y
now your integrand' numerator is √x which becomes siny
and the denominator is √1-sin²y ie √cos²y
ie cosy
so finally your integrand is sin y/cos y which is tan y and the limita are 0 to pi/4
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08/12/15
Jazzie G.
08/12/15