SURENDRA K. answered 07/18/15
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Three subintervals, so, n =3
a=0
b=3pi/4
(b-a)/n=pi/4
c1=pi/4
c2=pi/2
c3=3pi/4
Riemann sum=
(pi/4)[sin(2*pi/4)+sin(2*pi/2)+sin(2*3pi/4)]
(pi/4)[1+0-1]
=0