Michael J. answered 07/15/15
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We can eliminate choice (a), since not every value of f(x) is the same.
The y-intercept has the coordinate (0, y). We can eliminate choice (d) because if we plug in x=0, f(x) will be 1. We need he y-intercept to be (0, 3).
We now only have choice (b) and (c). The only function that has the y-intercept (0, 3) is f(x) = x + 3
Your answer is (c).