
David W. answered 07/11/15
Tutor
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(90)
Experienced Prof
This problem is about proportions. A proportion is usually expressed as a fraction or a percent or as “a:b” and it represents the number in one group compared to the total number.
There are 28 students in this class.
Prefer cookies = 12/28
Prefer ice cream = 10/28
Prefer peanuts = 6/28
With proportion problems, don’t do calculations that you don’t have to do. For example, don’t calculate what the above percentages are; let’s leave them as fractions for now.
For the entire school (population=312), we will assume that the same proportions exist. So:
Cookies 12/28 = C/3
28C = 3744 [cross multiply]
C = 133.7 rounded up is 134 cookies [divide both sides by 28]
Ice cream 10/28 = I/312
28C = 8736 [cross multiply]
I = 111.4 rounded up is 112 ice cream [divide both sides by 28]
Peanuts 6/28 = P/312
28P = 1872 [cross multiply]
P = 66.9 rounded up is 67 Peanuts [divide both sides by 28]
Just to check:
Is 134 + 112 + 67 enough for 312 students ? yes, it is 313
There are 28 students in this class.
Prefer cookies = 12/28
Prefer ice cream = 10/28
Prefer peanuts = 6/28
With proportion problems, don’t do calculations that you don’t have to do. For example, don’t calculate what the above percentages are; let’s leave them as fractions for now.
For the entire school (population=312), we will assume that the same proportions exist. So:
Cookies 12/28 = C/3
28C = 3744 [cross multiply]
C = 133.7 rounded up is 134 cookies [divide both sides by 28]
Ice cream 10/28 = I/312
28C = 8736 [cross multiply]
I = 111.4 rounded up is 112 ice cream [divide both sides by 28]
Peanuts 6/28 = P/312
28P = 1872 [cross multiply]
P = 66.9 rounded up is 67 Peanuts [divide both sides by 28]
Just to check:
Is 134 + 112 + 67 enough for 312 students ? yes, it is 313