(a). n! = n(n-1)(n-2)(n-3)...(3)(2)(1)
For example, 5! = (5)(4)(3)(2)(1) = 120
The number of combinations of a set of n objects taken r at a time = nCr
= n!/[r!(n-r)!]
(b). 6C3 =6![3!(6-3)!] = 720/[(6)(6)] = 720/36 = 20