Dion S.
asked 06/26/15y = 4x - 5
Find the derivative of each function
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1 Expert Answer
Jon P. answered 06/26/15
Tutor
5.0
(173)
Honors math degree (Harvard), extensive Calculus tutoring experience
There are 3 facts that determine the answer to this problem:
1. The derivative of a power of the independent variable (including a coefficient) is always as follows:
d/dx axn = naxn-1
2. The derivative of a constant function is 0
3. The derivative of a sum is equal to the sum of the derivatives.
So...
d/dx 4x = 4x0 = 4 * 1 = 4
d/dx 5 = 0
So...
d/dx (4x - 5) = 4 + 0 = 4
Dion S.
Mr Jon I am having trouble with this Calculus problem can you help me with it.
Find the derivative of each function.
y = 4/x2 + 1
Report
06/28/15
Jon P.
tutor
I assume this is 4/x2 + 1?
This is the same as 4x-2 + 1 and it works the same way as the previous one. The first term is a power of the independent variable, and it uses the same formula I gave above: d/dx axn = naxn-1. So for the first term, you get (-2)(4)x-2-1 = -8x-3 = -8/x3. For the second term, the derivative of 1 is 0. So the derivative of the complete function is -8/x3.
Report
06/29/15
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Dion S.
06/26/15