help me find the value of variable a

6(2a - 1) + 8 = 14;

12a - 6 + 8 = 14;

12a + 2 = 14;

12a = 12;

a = 1.

help me find the value of variable a

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6(2a - 1) + 8 = 14;

12a - 6 + 8 = 14;

12a + 2 = 14;

12a = 12;

a = 1.

6(2a - 1) + 8 = 14

12a - 6 + 8 = 14

12a + 2 = 14

12a + 2 - 2 = 14 - 2

12a = 12

12a/12 = 12/12

**a = 1**

When solving for a variable, the ultimate goal is to get the desired variable on one side of the equal sign and everything else on the other side. In order to do this, you need to do what's called the
*"i**nverse operation"* of everything next do the desired variable (for multiplication, this would be division; for addition, it would be subtraction; and vice versa). You need to perform the inverse operations in the
*reverse *order of operations (SADMEP as opposed to PEMDAS), and *anything you do to one side*
*you need to do to the other*.

We're given that 6(2a-1) +8 =14. The first task in our *reverse* order of operations is addition and subtraction. On the left-hand side, 8 is being
*added*. This means we need to perform the inverse of this addition: *subtraction*. Therefore we subtract 8 from
*both sides*. +8 and -8 cancel out on the left-hand side. 14 and -8 make 6 on the right-hand side.

We're left with 6(2a-1) = 6. Next in our reverse order of operations we have multiplication and division. On the left-hand side (2a-1) is being
*multiplied *by 6, so we should now do the inverse of that and *divide* both sides by 6. The 6's cancel out on both sides, leaving 2a-1 =1.

Of the operations left, addition and subtraction come first in reverse order of operations, so we'll do that next. 1 is being
*subtracted* on the left-hand side, so we should now *add* 1 to *
both *sides. It cancels on the left, and leaves 2 on the right.

Finally, we have 2a = 2. The last operation left is *multiplication*, so we should
*divide* by 2 on both sides. This leaves **a = 1** as our answer.

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