Bayes' Rule of Conditional Probability:
P(B|A)*P(A)
P(A|B) = -------------------
P(B)
Where:
- Proposition A = The person has no college degree
- Proposition B = the person randomly selected is a woman.
Hence we a re looking for the probability that the person selected has no college degree given that the person randomly selected is a woman.
First let's crunch some numbers. There are 710 employees:
- 130 employees have a college degree, 580 do not
- 130*0.4 = 52 women have a college degree
- 580*0.75 = 435 women do not have a college degree
- There are a total of 52+435 = 487 woman at the company
Now let's figure out P(B|A). This is the probability that the person chosen is a woman given that the chosen person has no college degree. There are 580 employees without a college degree, 435 of whom are women. Hence P(B|A) = 435/580
P(A) is the probability that the person chosen does not have a college degree. There are 710 total employees, 580 of whom do not have a college degree. Hence P(A) = 580/710
P(B) is the probability that the randomly chosen person is a woman. There are 710 employees, 487 of whom are women. Hence P(B) = 487/710
Now we're ready to use Bayes' Rule:
(435/580)*(580/710)
P(A|B) = --------------------------------- = 435/487 = 89.3%
(487/710)
Of course you could have done this more directly by taking the ratio of women without a college degree (435) to (over) the total number of women (487).