
David W. answered 06/10/15
Tutor
4.7
(90)
Experienced Prof
Hey! Thanks for “wanting to know!”
The most important part of a word (story) problem is translating the words into math expressions; after that, the math is easy.
We assume that each chicken and each pig has 1 head (I will verify this because a often fed chickens and pigs as a kid on our farm).
And, each chicken has 2 legs and each pig has 4 legs (live chickens and pigs, of course)
The problem gives the total number of legs (874) and asks for the number of chickens.
The number of chicken legs + the number of pig legs = 874
Or 2*numberofchickens + 4 *numberofpigs = 874
And for heads numberofchickens + numberofpigs = 295
Let’s shorten this, for math, by assigning variables C and P:
2C +4P = 874
C + P = 295
Now, you may either solve for P or C and substitute that value into the other equation or you may create a common coefficient of one of the variables and eliminate it by adding or subtracting equations. I like elimination, so let’s multiply the second equation and subtract equations:
2C + 4P = 874
2C + 2P = 590 (second equation multiplied by 2)
----------------------------- (subtract the two equations)
0 + 2P = 284
P = 142 (that’s a herd of pigs!)
Putting the number of pigs into the second equation:
C + 162 = 295
C = 153
Checking (very important):
Is 2*(153) + 4*(142) = 874 ?
306 + 568 = 874 Yes
The most important part of a word (story) problem is translating the words into math expressions; after that, the math is easy.
We assume that each chicken and each pig has 1 head (I will verify this because a often fed chickens and pigs as a kid on our farm).
And, each chicken has 2 legs and each pig has 4 legs (live chickens and pigs, of course)
The problem gives the total number of legs (874) and asks for the number of chickens.
The number of chicken legs + the number of pig legs = 874
Or 2*numberofchickens + 4 *numberofpigs = 874
And for heads numberofchickens + numberofpigs = 295
Let’s shorten this, for math, by assigning variables C and P:
2C +4P = 874
C + P = 295
Now, you may either solve for P or C and substitute that value into the other equation or you may create a common coefficient of one of the variables and eliminate it by adding or subtracting equations. I like elimination, so let’s multiply the second equation and subtract equations:
2C + 4P = 874
2C + 2P = 590 (second equation multiplied by 2)
----------------------------- (subtract the two equations)
0 + 2P = 284
P = 142 (that’s a herd of pigs!)
Putting the number of pigs into the second equation:
C + 162 = 295
C = 153
Checking (very important):
Is 2*(153) + 4*(142) = 874 ?
306 + 568 = 874 Yes
Maria Y.
Thank you!
Report
06/10/15
Maria Y.
06/10/15