
Reginald P. answered 06/05/15
Tutor
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Certified in Math and Physics, PhD Candidate in Engineering.
Let h = the height, so the base is b = h - 12
Area = A = 1/2(bh)
110 = (1/2)[h(h - 12)] = (1/2)h2 - 6h
h2 - 12h - 220 = 0, Solve using the Quadratic Formula or FOIL Method, to get x1 = -10 and x2 = 22
Choose 22, so the height is 22 and the base is b = 22 - 12 = 10 m
b = 10 m and h = 22 m
Check 110 = (1/2)(10)(22) = (1/2)220 = 110 m2

Andrew M.
06/06/15