The length of a rectangle is twice its width. If the area of the rectang le is 98 yd find its perimeter

Question

The length of a rectangle is twice its width. If the area of the rectangle is 98 yd² , find its perimeter 

Answer 1

Let the width of the rectangle be w.  Then its length, l=2w and its area=lw=2w^2=98.  So w=7.

The perimeter of the rectangle=2w+2l=2w + 2(2w)=6w=42 yards.