Bilal A.

asked • 06/03/15

pre cal simplify

     3                     5                                    n+3                6
                -                                                            +                 
x2+1x-2          x2+3x+2                           n2-5n+6         n2-7n+12
 
 
 

Andrew M.

The manner in which this question is typed is not clear.  What is the actual problem?
Is it...
 
1)  (x2 + x -2) - (x2 + 3x +2)
 
2)  (n2 - 5n + 6) + (n2 - 7n + 12)
 
Or are these 4 equations to simplify separately?  And what is the 3  5   n+3   6  ??
 
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06/04/15

Andrew M.

Or is this supposed to be
 
1)    3(x2 + x -2) - 5(x2 + 3x +2)
 
2)   (n+3)(n2 - 5n + 6) + 6(n2 - 7n + 12)
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06/04/15

1 Expert Answer

By:

Andrew M. answered • 06/04/15

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Mathematics - Algebra a Specialty / F.I.T. Grad - B.S. w/Honors

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3/(x2+x-2) - 5/(x2+ 3x + 2)
We can factor our denominators giving
 3/[(x+2)(x-1)] - 5/[(x+2)(x+1)]
Common denominator is (x+2)(x-1)(x+1) so multiply through by that
 
= 3(x+1)/[(x+2)(x-1)(x-1)] - 5(x-1)/[(x+2)(x-1)(x+1)]
= (3x +3-5x+5)/[(x+2)(x-1)(x+1)]
= (-2x + 8)/[(x+2)(x-1)(x+1)]
= -2(x-4)/[(x+2)(x-1)(x+1)]
 
You can follow same procedure for 2nd equation
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