
Andrew M. answered 06/04/15
Tutor
New to Wyzant
Mathematics - Algebra a Specialty / F.I.T. Grad - B.S. w/Honors
(2m2-7m-15)/(9-4m2)
To factor the numerator take the coefficient of the highest term (2, from 2m2) and
multiply it by the constant (-15) .. 2(-15) = -30
Look for factors of -30 that add to the coefficient (-7) of the m term
(-10)(3) are the applicable factors
Replace the -7m with -10m + 3m and factor by grouping
(2m2-7m-15) = 2m2 -10m + 3m -15 = 2m(m-5) + 3(m-5) = (2m+3)(m-5)
Factoring the denominator we have the difference of two squares
9-4m2 = 32 - (2m)2 = (3-2m)(3+2m)
combining back together we have
[(2m+3)(m-5)][(2m+3)(-2m+3)] = (m-5)/(-2m+3)
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Where does the *(3-2m) fit into the problem? Your format is unclear
If it is on the numerator of this problem then we have...
[(m-5)(3-2m)]/(3-2m) = m-5
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(2m2-10m)/6 = 2m(m-5)/6 = [m(m-5)]/3
If this is supposed to go together in another manner.... I apologize