pre cal simplify

Question

 x²-4                x²+x-6

            divide              

 x²-4x              x²+x-20

Answer 1

(x²-4)/(x²+x-6) = [(x-2)(x+2)]/[(x-2)(x+3)] = (x+2)/(x+3)

 

 

(x²-4x)/(x²+x-20) = [x(x-4)]/[(x+5)(x-4)] = x/(x+5)